What is the period of the function y 2 sin 3x pi6 4 pi6 1

What is the period of the function y = 2 sin (3x - pi/6) + 4? pi/6 1/2 2pi/3 pi 2 pi

Solution

Solution:

as we know that period of the sin function 2

thus period of sin(x) = 2

therefore period of 2sin(3x-/6) + 4

3x = 2

x = 2/3

thus period of above function =2/3

Answer: Period : 2/3