Homework SourseTwo objects are rolled along a horizontal surface billiard b
Two objects are rolled along a horizontal surface: billiard ball mass 0.20kg; radius 2.7 cm. cylindrical rod: mass, 0.40 kg; radius 0.5 cm the ratio of their moments of inertia ball/cyl is ?
Two objects are rolled along a horizontal surface: billiard ball mass 0.20kg; radius 2.7 cm. cylindrical rod: mass, 0.40 kg; radius 0.5 cm the ratio of their moments of inertia ball/cyl is ?
Solution
Moment of inertia of a ball = (2/5) * M.R^2
= (2/5) * 0.20 * (2.7* 10^-2)
= 0.5832 * 10^-4 kg m2
Moment of inertia of a cylinder = 1/2 *m. r^2
= 0.5 * 0.4 * (0.5 * 10^-2)
= 0.05 * 10^-4 kg m2
Ratio of inertia = Moment of inertia of a ball / Moment of inertia of a cylinder
= 0.5832 * 10^-4 / 0.05 * 10^-4
= 11.664
