a 500 ml volume of 015 M HBr is titrated with 250 M KOH Calc

a 50.0 ml volume of 0.15 M HBr is titrated with 25.0 M KOH. Calculate the ph after the addition of 10.0 ml KOH.

moles HBr = 0.0500 L x 0.15 M=0.0075
moles KOH = 0.0140 L x 0.25 M=0.0035
moles H+ in excess = 0.0075 - 0.0035 =0.0040
total volume = 0.064 L
[H+]= 0.0040/ 0.064 =0.0625 M
pH = 1.2