consider the line y65x8 find the equation of the line that i

consider the line y=-6/5x+8

find the equation of the line that is parallel to this line and passes through the point (-6,-6)

find the equation to the line that is perpendicular to this line and passes through the point (-6,-6)

given line equation is y =-5x +3

the slope of this equation is -5 since this is of the form y=mx+c (where m =slope of the line)

parallel lines have same slopes

so we need to find the line of slope = -5 & passing through (-8,-3)

y =-5x +c is passing through (-8,-3)

-3 =-5(-8) +c

-3 = 40 +c

c= -43

so parallel line is y= -5x -43

5x +y =-43 is parallel line

the slope of perpendicular line is -1/m = -1/(-5) =1/5

the equation is y =1/5 x + c is passing through (-8,-3)

-3 = -8/5 +c

c= -3+8/5

c=-7/5

y= 1/5x -7/5

5y = x -7

x -5y -7=0 is the perpendicular line