What volume in L of 011 M CaOH2 is required neutralize 029 m

What volume in L of 0.11 M Ca(OH)₂ is required neutralize 0.29 moles of HCl? The balanced reaction is:

2HCl(aq) + Ca(OH)₂(aq) → 2H₂O(l) + CaCl₂(aq)

Solution

1 mole of Ca(OH) 2 neturalses 2 moles og HCl

so moles of Ca(OH)2 required = 0.29/2 = 0.145 moles

moles = molarity * volume

volume = 0.145/0.11 = 1.318 L