A jar contains 60 nickels and dimes worth 530 How many of ea

A jar contains 60 nickels and dimes worth $5.30. How many of each kind of coin are in the jar? x = nickels y = dimes

Solution

Let there be \'x\' nickels and \'y\' dimes.

We are given that the total number of coins is 60.

So, x + y = 60 ------------------------ (i)

We know that $0.05 = 1 nickels and $0.1 = 1 dimes.

And, the value of the 60 coins is = $5.30.

So, we can write -

0.05(x) + 0.1(y) = 5.3-------------(ii)

So, we have got two equations and two unknown variables. Multiply the first equation with 0.05 to get -

0.05(x) + 0.05(y) = 3 -------- (iii)

Subtract (iii) from (ii) to get -

0.05(y) = 2.3

=> y = 46

Putting y=46 in equation (i) we get -

x + 46 = 60

=> x = 14.

Hence there are 14 nickels and 46 dimes in the jar.

So, x=14 nickels and y=46 dimes.