Solve this equation log3x log3 2x32Solutionyour question is

Solve this equation log3^x + log3 (2x+3=2

your question is not formated properly
Its looks like:
log3^x + log3 (2x+3)=2
log3^x + (2x+3)log3 =2
x log3 + (2x+3)log3 =2
log 3 (x + 2x+3) = 2
3x+3 = 2/log 3
3(x+1) = 2/log 3
x+1 = 2/(3*log 3)
x = (2/(3*log 3)) - 1