Find the function fx ax3 bx2 cx d for which f3 135 f1
Solution
We get, on substituting the given x-values,one by one, in the equation , f(x)= ax3+bx2+cx+d, as under:
Now, let A be the augmented matrix of the above linear system. Then A =
-27
9
-3
1
-135
-1
1
-1
1
1
1
1
1
1
9
8
4
2
1
25
In order to solve the above linear system, we will reduce A to its RREF as under:
Multiply the 1st row by -1/27; Add 1 times the 1st row to the 2nd row
Add -1 times the 1st row to the 3rd row; Add -8 times the 1st row to the 4th row
Multiply the 2nd row by 3/2; Add -4/3 times the 2nd row to the 3rd row
Add -20/3 times the 2nd row to the 4th row; Multiply the 3rd row by 3/8
Add -10 times the 3rd row to the 4th row; Multiply the 4th row by -1/5
Add 1/3 times the 4th row to the 3rd row; Add -13/9 times the 4th row to the 2nd row
Add 1/27 times the 4th row to the 1st row; Add 4/3 times the 3rd row to the 2nd row
Add -1/9 times the 3rd row to the 1st row ; Add 1/3 times the 2nd row to the 1st row
Then the RREF of A is
1
0
0
0
4
0
1
0
0
-4
0
0
1
0
0
0
0
0
1
9
Hence, a = 4,b = -4, c = 0 and d = 9. Then, the required function is f(x)= 4x3-4x2+9.
| -27 | 9 | -3 | 1 | -135 |
| -1 | 1 | -1 | 1 | 1 |
| 1 | 1 | 1 | 1 | 9 |
| 8 | 4 | 2 | 1 | 25 |

