Question 2 A firm wants to buy a machine costing 100000 The
Solution
Solution: Cost of machine, IC = $100,000
Annual maintenance cost = $5,500, Annual revenues = $20,000, so anuual returns, AR = 20000 - 5500 = $14,500
Salvage value, SV = $8,000; life period, N= 10 years; MARR = 12%
To check if deal is good, or firm should invest in this machine, we calculate IRR (Internal rate of return).
If IRR > MARR, the deal is good, and this investment should happen ... (1)
Present worth,PW = -IC + AR(P/A,i,N) + SV(P/F,i,N)
IRR is rate for which present worth = 0
PW of this machine = -100,000 + 14,500 (P/A,12%, 10) + 8,000 (P/F, 12%, 10)
For IRR, 100,000 = 14,500 (P/A,i,10) + 8000 (P/F, i,10)
(P/A,i,10) = ((1+i)10-1)/i(1+i)10
(P/F,i,10) = (1+i)-10
so, 100000 = 14500*((1+i)10-1)/i(1+i)10 + 8000 (1+i)-10
On solving, we get i = 0.0821 (approx). So, IRR = 8.21% < 12% = MARR
Following (1), the firm shouldn\'t invest.
