Find dydx y 6sec x tan xsec x tan x dydx Solutiony 6 se

Find dy/dx. y = 6(sec x + tan x)(sec x - tan x) dy/dx =

y = 6 (sec x + tan x)(sec x - tan x)

Using formula,

(a+b)(a-b) = a^2 - b^2

We will get

y = 6 ( sec^2x - tan ^2x)

Using identity, sec^2 - tan^2x = 1

We get

y=6

Now, differentiating it,

dy/dx = d6/dx

And differentiation of constant is 0.

So, dy/dx = 0