05 Question s points Seepage 246 A semiprofessional basebal
Solution
Question 5
PART 1
Average attendance per game = 30 people
Price of each ticket = $10
Total receipts from tickets = 30 * $10 = $300
Average spending at concession stand = $6
Total receipts from concession stand = $6 * 30 = $180
Team keeps 50 percent receipts from concession stand.
So,
Receipts from concession stand to team = $180/2 = $90
Total revenue from each game = $300 + $90 = $390
Each month team plays two home games. The season is of three months.
So, a total of six games is played.
Total revenue from each season = $390 * 6 = $2,340
Rent paid to city each month = $100
Total rent paid for whole season = $100 * 3 = $300
Salaries paid each month = $1,000
Total salaries paid for whole season = $1,000 * 3 = $3,000
Total cost = $300 + $3,000 = $3,300
Profit = Total revenue - Total cost = $2,340 - $3,300 = -$960
So,
The team earns an average of $390 in revenue from each game and $2,340 of revenue each season.
With total costs of $3,300 each season, the team finishes the season with -$960 of profit.
PART 2
At break-even, total revenue equals total cost.
Let the number of tickets to be sold to breakeven be x
Total revenue from each game = ($10 * x) + ($6 * x)/2 = 10x + 3x = 13x
Total revenue from whole season = 13x * 6 = 78x
Total cost = $3,300
At break-even,
Total revenue = Total cost
78x = 3,300
x = 3,300/78 = 42.30 or 42 tickets
So,
In order to break even, the team needs to sell 42 tickets for each game.

