The value of AH for the reaction below is 336 kJ Calculate t

The value of AH for the reaction below is -336 kJ. Calculate the heat (k) released to the surroundings when 23.0 g of HCl is formed. CH4 (g) + 3Cl2 (g) CHCl3 (1) + 3HC1(g) A) 2.57 x 103 B) 70.7 C) 177 D) 211 E) -336

Solution

moles = mass / molar mass

so

moles of HCl formed = 23 g / 36.46 (g/mol)

moles of HCl formed = 0.6308 mol

now

heat released = 0.6308 mol HCl x 336 kJ / 3 mol HCl

heat released = 70.65 kJ

so

the answer is B) 70.7 kJ