You have a solution of 110 ppM Formaldehyde CH2O a tissue pr

You have a solution of 11.0 ppM Formaldehyde (CH2O, a tissue preservative). You dilute 3.00 mL of this solution to a volume of 1.00 L. What is the ppB of the new Formaldehyde solution? You dissolve 101.6 mg of Auric Fluoride to 2500. mL. What is this solution\'s Molarity Auric Fluoride? Molarity Fluoride? What is its ppM Auric Fluoride? If you were to dilute 20.0 mL of this solution to 5000. mL, what is the ppB of the Fluoride?

Solution

Initial Concentration = 11 ppM = 11 mg/L

Mass of Formaldehyde in 3 mL = 3 x 11 / 1000 = 0.033 mg

New Volume of solution = 1 L

1 ppM = 1000 ppB

New Concentration = 0.033 mg/L = 0.033 ppM = 33 ppB

Solution\'s Molarity Auric Fluoride = 101.6 / 2.500 = 40.64 mg/L = 40.64 ppM

After Dilution,

New concentration = 0.02 x 40.64 x 1000 / 5 = 162.56 ppB