2 Using the ideal gas law calculate the moles of O2 collecte
2. Using the ideal gas law calculate the moles of O2 collected “blank” mol O2
A. Order of Reaction BATH TEMPERATURE Solution 1 Buret (mL) reading Vol. ofO2 (mL) Time 10.0 000- GO ) 51K 62 Slope Slope= 1 . 867 Solution
Here you got the slope is rate constant, Rate or r = k [concentration]
k1 = 1.807 and k2 =0.0642
then compare k1 and k2 to compare rates
k1/k2 = 1.807/0.0642 = 28.14641
rate of solution 1 is 28 times fatter than Solution 2
Ideal gas equation , PV = nRT
P is the pressure = 298 Hg = 0.3921 atm
V is the volume = 14 ml
n = number of moles. ?
R = universal gas constant( 0.08205 L atm / mol·K)
T is the temperature =33 + 273 = 306 K
solution is
n = PV/RT = (0.3921 x 0.014 L) / (0.08205 x 306 K )
= 0.0054894/ 25.245 = 0.000217429 moles of oxygen.
