Find an equation for a line that is perpendicular to fx5x1an

Find an equation for a line that is perpendicular to f(x)=5x-1and passing through the point (5,20)

Equation for a line that is perpendicular to f(x)=5x-1and passing through the point (5,20)

The slope of line y =5x-1 is 5

as the equation y = mx + c represents a straight line graph on the xy plane with slope m and intercept c.

m = 5

The negative reciprocal of that slope is: -1/5

New slope is the slope of the equation that is perpendicular to the line equation f(x)=5x-1

The point-slope form of the equation of a straight line is: y y1 = m(x x1) , with slope m and passing through point (x1 , y1)

In the question , given information is

(x1 , y1) = ( 5 , 20)

and the slope is m = -1/5

Equation of line is ( y - 20 ) = (-1/5) ( x - 5)

=> 5y - 100 = -x + 5

=> 5y = - x + 105

=> y = -x/5 + 21 is the equation of a line that is perpendicular to y=5x-1