Find the vector components of u 2 0 1 along a 1 2 3 and th
Solution
In order to show that the two components that we have found are orthogonal or not we need to check if these
two vector components dot product is 0 or not.
If its 0 then it\'ll imply that the two vectors are perpendicular to each other or they are orthogonal to each other
the component of u along a is = <5/14 , 5/7 , 15/14>
the component of u orthogonal to a is = <23/14 , -5/7 , -1/14>
now find the dot product
<5/14 , 5/7 , 15/14> . <23/14 , -5/7 , -1/14> = 115/14^2 - 25/7^2 - 15/14^2 = 5/49*[23/4 - 5 - 3/4]
= 5/49*[(23 - 20 - 3)/4]
= 5/49*[0] = 0
Since the dot product is 0 so we can say that the two components are orthogonal to each other.
