Suppose that 460nm light strikes a metal resulting in ejecte

Suppose that 460-nm light strikes a metal, resulting in ejected electrons having a maximum kinetic energy of 1.70 eV. What would be the work function of the metal (in eV)? explain please answer should be

work function is = 1.00 eV

Solution

Here,

wavelength = 460 nm

Now , for the energy of photon

energy of photon = h * c/(wavelength * e)

energy of photon = 6.626 *10^-34 * 3 *10^8/(460 *10^-9 * 1.602 *10^-19)

energy of photon = 2.697 eV

maximum kinetic energy of electron = 1.70 eV

work function of metal = energy of photon - maximum kinetic energy

work function of metal = 2.697 - 1.70

work function of metal = 0.997 eV

the work function of metal = 1 eV

the work function of metal is 1 eV