A wire is connected between the terminals of a 9 V battery a

A wire is connected between the terminals of a 9 V battery, and the potential difference pushes electrons through the wire. If 7.47 × 10^20 electrons flow past any point along the wire during a time of 2.23 s, what is the current in the wire? What must be the resistance of the wire? (current needs to be in A, resistance in ohms) Thanks!

Solution

According to the give problem,

As the electrons are flowing throught the wire, there will be a charge,

Q = 7.47 *10²⁰* charge of electron(1.602 *10^-19C)

Q = 119.6694C

As there is a charge present, there will be current in the wire,

I = Q/t

I = 119.6694C/2.23s

I = 53.663A

As there is current and a voltage is applied, there must be some resistance,Using Ohms law,

R = V/I

R = 9V/53.663A

R = 0.1677