An emf of 160 mV is induced in a 483turn coil when the curre

An emf of 16.0 mV is induced in a 483-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux through each turn of the coil at an instant when the current is 3.50 A?

Solution

Induced EMF = |E| =L(I/t)

We need to find the self-inductance :

L = |E|I/t put in the values we get

L = (16.0 * 10 ^ -3 V) * ( 10.0 A/s)

L = 1.6 *10 ^ -3 H

Now we find the magnetic flux through each turn:

B =L · I/ N

we have the value of L and N put in the equation above:

B= (1.6 *10 ^ -3 H ) * ( 3.50 A) / 483

B= 1.1594 * 10 ^ -5 T·m2 =============================answer)