A bomb calorimeter consists of metal parts with a heat capac

A bomb calorimeter consists of metal parts with a heat capacity of 950.0 J degree C^-1 and 8.50 Times 10^2 grams of oil with a specific heat of 2.418 J g^-1 degree C^-1. Calculate the amount of heat energy required, in kJ, to raise its temperature from 25.00 degree C to 31.60 degree C.

Solution

increment of temperature 31.6 - 25 = 6.60 C

Q = (850 g)*(6.60 C) (2.418 J/g °C) = 13564.98 J

The calorimeter absorbs some energy

(950.0 J /C)*(6.60 C) = 6270 J

total energy required = 13564.98 J + 6270 J = 19834.98 J = 19.8 kJ