A voltage of 11 V is placed on a capacitor with C 113 pF pi

A voltage of 11 V is placed on a capacitor with C = 113 pF (picofarads).

(a) What is the charge on the capacitor?
1.243e-9 C

(b) How much energy is stored in the capacitor?
????

Solution

Given that V = 11 V

and C = 113 pF

a) charge is Q = C*V = 11*113*10^-12 = 1.243*10^-9 C

b) energy stored is U = 0.5*C*V^2 = 0.5*113*10^-12*11^2 = 6.84*10^-9 J