A battery with an emf of 60 V is connected to the two capaci

A battery with an emf of 60 V is connected to the two capacitors shown, afterward , the charge on capacitor 2 is 450 uC. What is the capacitance of capacitor 2? ( assume ideal battery)

Solution

as capacitors are in series ,so same charge flows through both the capacitors.So Voltage across 12 uF is

V₁₂=Q/C₁₂=450/12 =37.5 Volts

Voltage across C₂ is

V₂=V-V₁₂=60-37.5 =22.5 Volts

so capacitance of capacitor c2 is

C₂=Q/V₂=450/22.5

C₂=20 uF