Consider the following reaction 4NH3g 7O2g 2N2O4g 6H2Og If

Consider the following reaction:
4NH3(g) +7O2(g) <--> 2N2O4(g) + 6H2O(g)
If the intial concentrations of NH3(g) and O2(g) are 3.60M atequilibrium the concentration of N2O4(g) is 0.60 M Calculate theequilbrium concentration of NH3(g)

A) 1.8 M
B) 3.3 M
C 1.5 M
D) 2.4 M
E) 3.0 M

Solution

                                                  4NH3(g) +7O2(g) <--> 2N2O4(g) + 6H2O(g)
                                         I(M)    3.60        3.60               0                0
                                        C(M)     -4x         -7x              +2x            +6x
                                        E(M)    3.60 - 4x 3.60 -7x       +2x            +6x
At equilibrium , [N2O4(g) ] = 0.60 M
                                 2x      = 0.60 M
                                   x      = 0.60 M /2
                                           = 0.30 M
equilbrium concentration of NH3(g ) = 3.60 M - 4 * 0.30 M
                                                              = 3.60 M - 1.20 M
                                                             = 2.4 M

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