Consider the following reaction 4NH3g 7O2g 2N2O4g 6H2Og If
Consider the following reaction:
4NH3(g) +7O2(g) <--> 2N2O4(g) + 6H2O(g)
If the intial concentrations of NH3(g) and O2(g) are 3.60M atequilibrium the concentration of N2O4(g) is 0.60 M Calculate theequilbrium concentration of NH3(g)
A) 1.8 M
B) 3.3 M
C 1.5 M
D) 2.4 M
E) 3.0 M
4NH3(g) +7O2(g) <--> 2N2O4(g) + 6H2O(g)
If the intial concentrations of NH3(g) and O2(g) are 3.60M atequilibrium the concentration of N2O4(g) is 0.60 M Calculate theequilbrium concentration of NH3(g)
A) 1.8 M
B) 3.3 M
C 1.5 M
D) 2.4 M
E) 3.0 M
Solution
4NH3(g) +7O2(g) <--> 2N2O4(g) + 6H2O(g)
I(M) 3.60 3.60 0 0
I(M) 3.60 3.60 0 0
C(M) -4x -7x +2x +6x
E(M) 3.60 - 4x 3.60 -7x +2x +6x
At equilibrium , [N2O4(g) ] = 0.60 M
2x = 0.60 M
x = 0.60 M /2
= 0.30 M
equilbrium concentration of NH3(g ) = 3.60 M - 4 * 0.30 M
= 3.60 M - 1.20 M
= 2.4 M