4 ANOVA test performed determined that not all mean commute

4. ANOVA test performed determined that not all mean commute times across the four cities are equal. However, it did not indicate which means differed. To find out which population means differ requires further analysis of the direction and the statistical significance of the difference between paired population means. Tukey 95% confidence intervals are shown below.

How many pairs of cities show a significant difference in average commute times to work?

Answer: 3

how did the teacher find this? formulas please

Lower Upper Houston-Charlotte 11:22 | 63:78 Tukey\'sHouston - Tucson23.0575.62 Houston-Akron37.0589.62 confidence Charlotte- Tucson-14.4538.12 0.45 52.12 12.2840.28 95% intervals Charlotte Akron Tucson - Akron

Solution

To calculate this, you need to know a threshold difference which may have been provided in the problem or calculated by the teacher earlier.

Once you know that threshold, any pair greater than that threshold shows a significant difference.

4. ANOVA test performed determined that not all mean commute times across the four cities are equal. However, it did not indicate which means differed. To find

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site