A particular bug doubles the population every 7 hours A scie

A particular bug doubles the population every 7 hours. A scientist started with 670 of these bugs.

(1) How many bugs will there be in 11.4 hours.....................? round to nearest whole number.

(2) What would the percent per hour be for F=Pe^{rt}, in other words what is r as a the rate? Round to the nearest 10th of a percent.............................. % per hour

Solution

1.

Here,

P = Po [2^(t/7)]

As Po = 670, t = 11.4,

P = 670*2^(11.4/7) = 2072 [ANSWER]

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2.

As

(1+r)^7 = 2

Then

1+r = 1.104089514

r = 0.104089514 or 10.4% [ANSWER]