Show steps and explanation please Thank you so muchSolutionl

Show steps and explanation please! Thank you so much!

Solution

l = 3 m, Mass of Wooden beam m = 10 kg

Consider balance point b = l/2 = 3/2 = 1.5

l₁ = l₂ = 1.5 m

At balancing point mass also shared as m₁ = m₂ = 10 /10= 1 kg

Additional 20 kg weight on the Wooden beam is placed at the left end.

So left side effective length and mass values will be changed.

m₁ = 1 + 20 = 21 kg

l₁ = 1.5 - 0.5 = 1 m

Wooden beam weight on left side for full length left side w_{1 =} m₁ g

w₁ = 21 * 10 = 210 N