Write a program that uses the array of numbers from problem

Write a program that uses the array of numbers from problem 1. Then compute the following properties on the set of numbers: the sum, the average (mean), the variance, the standard deviation, and the median. Don\'t try to do the entire program at once. Build a little, test a little. Your program should contain 5 functions(methods). One method to compute the sum, a method to compute the average (mean), a method to compute the variance, a method to compute the standard deviation, and finally a method to compute the median. The method to compute the median should work regardless of whether n is even or odd, where n is the length of the array. Example for an odd sized array: {5, 7, 8, 9, 2} sum = 31.0 average (mean) = 6.2 Variance = [(5 - 6.2)^2 + (7 - 6.2)^2 + (8 - 6.2)^2 + (9 - 6.2)^2 + (2 - 6.2)^2]/5.0 = [(1.44) + (0.64) + (3.24) + (7.84) + (17.64)]/5.0 = 30.8/5.0 = 6.16 Standard Deviation = the squareroot of 6.16 = 2.482 The median for {2, 5, 7, 8, 9} is 7

Solution

Solution:

#include <iostream.h>

#include<math.h>

double sum (double sum_arr[], int sum_arr_sz)

{

int i;

double total;

// summing up the data

for (i=0; i<sum_arr_size; i++)

total = total + sum_arr[i];

return total;

}

double average( double avg_arr[], avg_arr_sz)

{

int i;

double total, averg;

// summing up the data

for (i=0; i<avg_arr_size; i++)

total = total + avg_arr[i];

//calculating average

averg= total / (double)avg_arr_size

return averg;

}

double variance(double var_arr[],double avg, int var_arr_sz)

{

int i;

double total,variance;

for (i = 0; i < var_arr_sz; i++)

{

return variance;

}

double std_deviation( double variance)

{

int i;

double std_devn;

std_devn = sqrt (variance);

return std_devn;

}

double median(med_arr[], int med_arr_sz)

{

double* sort_arr = new double[med_arr_sz];

for (int i = 0; i < med_arr_sz; ++i)

{ sort_arr[i] = med_arr[i];

}

for (int i = med_arr_sz - 1; i > 0; --i)

{

for (int j = 0; j < i; ++j)

{

if (sort_arr[j] > sort_arr[j+1])

{

double sort_temp = sort_arr[j];

sort_arr[j] = sort_arr[j+1];

sort_arr[j+1] = sort_temp;

}

}

}

// average of middle values in the sorted array

double Med = 0.0;

if ((med_arr_sz % 2) == 0)

{

Med = (sort_arr[med_arr_sz/2] + sort_arr[(med_arr_sz/2) - 1])/2.0;

}

else

{

Med = sort_arr[med_arr_sz/2];

}

delete [] sort_arr;

return Med;

}

int main()

{

double Arr_Values[] = {33.5, 67.5, 67.5, 88.0, 46.0, 94.5, 77.5, 83.0, 95.0, 80.5};

double sum_ret, avg_ret, var_ret;

int Array_Size = 10;

sum_ret = Sum(Arr_Values, Array_Size)

std::cout << \"Sum = \" << sum_ret<< std::endl;

avg_ret = average(Arr_Values, sum_ret, Array_Size)

std::cout << \"Average(mean) = \" << avg_ret << std::endl;

var_ret= variance(Arr_Values, avg_ret, Array_Size)

std::cout << \"Variance = \" << var_ret << std::endl;

std::cout << \"Standard Deviation= the square root of\"<<var_ret << \"=\" << std_deviation(var_ret)<< std::endl;

std::cout << \"Median = \" << median(Arr_Values, Array_Size) << std::endl;

return 0;

}