Solve for all resistors please make a table containing value

Solve for all resistors; please make a table containing values also.

R, I, V

2.0 3.0 5.0 1.0

3 and 4 ohms are in parallel.So, resultant of these two is R = (3x4)/(3+4)

= 1.7142 ohm

R and 5 ohm are in parallel.So, resultant of these two is R \' = (1.7142 x5)/(1.7142 +5)

= 1.2766 ohm

R \' , 2 ohm and 1 ohm are in series.So, equivalent resistance R \" = R \'+ 2 + 1

= 1.2766 + 3

= 4.2766 ohm

(b). Current through the circuit i = V / R \"

= 12 volt / 4.2766 ohm

= 2.805 A

Current through 2 ohm is = i

= 2.805 A

Current through 1 ohm is = i

= 2.805 A

Current through R \' is = i = 2.805 A

Current through 5 ohm is = i[R /(R+5)]

= 2.805 [1.7142 /(1.7142+5)]

= 0.7163 A

Current through R is i \' = i[5/(R+5)]

= 2.805 [5/(1.7142+5)]

= 2.088 A

Current through 3 ohm is = i \'[4/(3+4)]

= 1.193 A

Current through 4 ohm is = i \'[3/(3+4)]

= 0.8952 A

Voltgae across 2 ohm is = V[2/(2+R \' + 1 )]

= 12 [2 /(2+1.2766 +1)]

= 12[2 /4.2766]

= 5.611 volt

Voltgae across 1 ohm is = V[1/(2+R \' + 1 )]

= 12 [1 /(2+1.2766 +1)]

= 12[1 /4.2766]

= 2.805 volt

Voltgae across R\' ohm is = V[R \'/(2+R \' + 1 )]

= 12 [1.2766 /(2+1.2766 +1)]

= 12[1.2766 /4.2766]

= 3.582 volt

So, Voltage across 5 ohm is = 3.582 volt