The pointPx y is on the unit circle in Quadrant IV If x fin

The pointP(x, y) is on the unit circle in Quadrant IV. If x =

find y.

91/10

Solution

here x,that is cos theta= sqrt91/10

                 adjacent=sqrt 91 and hypotenuse=10

therefore opposite=sqrt(10^2 - sqrt91^2)= 3

And sin theta is negative in fourth quadrant

therefore sin theta=-3/10

And that\'s the value of y.