An electron that has a velocity with x component 28 Times 10

An electron that has a velocity with x component 2.8 Times 10^6 m/s and y component 2.3 Times 10^6 m/s moves through a uniform magnetic field with x component 0.026 T and y component -0.22 T. (a) Find the magnitude of the magnetic force on the electron, (b) Repeat your calculation for a proton having the same velocity. (a) Number Units (b) Number Units

Solution

A) x component velocity= 28×10⁶m/s. B=0.026T. Y component velocity=23×10⁶m/s. B=0.22T. Charge of electron =_ 1.6× 10^_19c. Angle= 90°. F=qvB sin teeta. F=_1.6×10^_19×28×10⁶×0.026= 1.1648×10^_13N B) F=qvB sin teeta= 1.6×10^_19×23×10⁶×0.22. = 8.096×10^_13N