Homework Soursefind the curvature and the radius of the curvature of the cu
find the curvature and the radius of the curvature of the curve y=ln(3x-2) at the point P(1,0).
Solution
dy/dx = 3/(3x-2) y\' (1,0)= 3/(3-2)=3 y\'\'= -{3/(3x-2)^2 } 3 y\'\'(1)= -9/(1) =-9 Radius of curvature = | (1+y\' ^2) ^3/2/y\'\' | = (1+9)^3/2 / 9 =10^1.5/9 =3.51 curvature = 1/ Radius of curvature =0.285
