In the analysis of variance table in which 4 means are being

In the analysis of variance table in which 4 means are being tested for equality based on samples of size 6 from each of the 4 populations, the degrees of freedom for error is:

18

21

19

20

none of the above is correct

Solution

df(treat) = k-1 = 3

df(total) = n-1 = 24-1 = 23

df(error) = df(total) - df(Treat) = 23 - 3 = 20