a box has 8 red balls and 2 green balls a ball is selected a

a box has 8 red balls and 2 green balls. a ball is selected and replaced. then a second one is drawn. what is the probability of getting a red then a green?

Solution

8 red
2 green

P(red and then green) = (8/10) * (2/10) = 16/100 = 4/25

Now, when two draws are done, we can get red,green or greeen,red

So, divide that probability by 2 :

(4/25) divided by 2

2/25 ---> ANSWER