In an ionic solution 48 1015 positive ions with charge 2e pa

In an ionic solution, 4.8 10^15 positive ions with charge +2e pass to the right each second while 5.1 10^15 negative ions with charge -e pass to the left. What is the current in the solution? in mA.

Solution

current in the solution is calculated as follows\":

       I = q/t

         = (4.8x10^15*2*1.60x10^-19 + 5.1x10^15*1.60x10^-19)/1.0s

         = 2.352e-3 A

         = 2.352 mA