A water rocket is shot vertically upward with an initial vel

A water rocket is shot vertically upward with an initial velocity of 90 m/s. What is its maximum height?

Max Height = XXX meters

Solution

solution:

initial velocity,u = 90 m/s

now at maximum height h, its velocity will be 0

hence v=0

now

using newtons third law

v²-u²=2as

here a= acceleration is acceletration due to gravity= -g

and s= maximum height = h

hence

v²-u²=-2gh

g=9.8 m/sec²

0-90²=-2(9.8)h

-8100=-19.6h

h=413.265 m