let X p and q or r and Z be r or p and q We would like to f
let X = \"p and (q or r)\" and Z be \"r or (p and q)\".
We would like to find a good first step in a deductive sequence proof that X --> Z.
That is, we need a statement Y such that (1) Y follows from X by a rule, and (2) Y --> Z is true. Which one of these choices of Y fits these two conditions?
Choose one:
a. Y = p and q
b. Y = r
c. Y = (p and (q or r)) or r
d. Y = p
Solution
Hence we can see that p=1, all the values of X and Z are same
Hence y = p will be the choice, since it follows from X by a rule and also Y->Z is true
| P | Q | R | X | Z |
| 0 | 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 0 | 1 |
| 0 | 1 | 0 | 0 | 0 |
| 0 | 1 | 1 | 1 | 1 |
| 1 | 0 | 0 | 0 | 0 |
| 1 | 0 | 1 | 1 | 1 |
| 1 | 1 | 0 | 1 | 1 |
| 1 | 1 | 1 | 1 | 1 |
