Find the exact value of cos theta tan theta 45 theta in qua

Find the exact value of cos theta tan theta = -4/5, theta in quadrant II -squareroot 41/5^5 squareroot 41/41 squareroot 41/4 -^5 squareroot 41/41

tan theta=-4/5 theta is in second quadrant

Here opposite=4 and adjacent=5

hypotenuse=sqrt(16+25)=sqrt41

cos theta is negative in second quadrant

cos theta=adjacent/hypotenuse= - 5/sqrt41

Correct option is D