Albinism is a skin pigmentation disease and is controlled by

Albinism is a skin pigmentation disease and is controlled by a single gene. Albinism is a recessive trait and the mutant form is a. Consider a marriage between two normal individuals, both of whom are known carriers for the mutant form (Aa).   

h.In a study on a large number of families with heterozygous parents, a total of 88 normal and 72 albino children were observed. Do the numbers deviate significantly from expected? Calculate the Chi square value, degrees of freedom, and probability.

Solution

.In a study on a large number of families with heterozygous parents, a total of 88 normal and 72 albino children were observed. Do the numbers deviate significantly from expected? Calculate the Chi square value, degrees of freedom, and probability

Aa x Aa

A

a

A

AA

Aa

a

Aa

aa

observed

expected

(O-e)^2 /e

normal

AA , Aa

88

120

(88-120)^2 /120

8.53

88

aa

72

40

(72-40)^2 /40

25.6

160

160

34.13

Calculated Chi square value-------34.13

Which is more than table value at 5% level of significance

Hence reject the null hypothesis

A

a

A

AA

Aa

a

Aa

aa

Albinism is a skin pigmentation disease and is controlled by a single gene. Albinism is a recessive trait and the mutant form is a. Consider a marriage between
Albinism is a skin pigmentation disease and is controlled by a single gene. Albinism is a recessive trait and the mutant form is a. Consider a marriage between

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