It is friction that provides the force for a car to accelera

It is friction that provides the force for a car to accelerate, so for high-performance cars the factor that limits acceleration isn\'t the engine; it\'s the tires. For typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 60 mph? Suppose that s=1.00 and k=0.80.

Solution

the frictional force:

       fr = 0.02*Fnormal

frictional force:

fs = m*g = 9.8* mass of car

so, the net force is,

Fnet =9.8m -(0.02)(9.8m),

m*a = 9.8m -(0.02)(9.8m)

a = 9.8 - 0.02*9.8

a = 9.604 m/s^2.

hence, the time is calculated as follows:

         Vf = Vo + at,

      (26.8224) = 0 + 9.604*t     (since, mph = 0.44704 m/s)

                    t = 2.8 s.

It is friction that provides the force for a car to accelerate, so for high-performance cars the factor that limits acceleration isn\'t the engine; it\'s the ti

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