A blue car with mass mc 435 kg is moving east with a speed

A blue car with mass m_c = 435 kg is moving east with a speed of v_c = 21 m/s and collides with a purple truck with mass m_t = 1298 kg that is moving south with a speed of v_t = 10 m/s . The two collide and lock together after the collision.

1) What is the magnitude of the initial momentum of the car?

kg-m/s

2) What is the magnitude of the initial momentum of the truck?

kg-m/s

3) What is the angle that the car-truck combination travel after the collision? (give your answer as an angle South of East)

°

4) What is the magnitude of the momentum of the car-truck combination immediately after the collision?

kg-m/s

5) What is the speed of the car-truck combination immediately after the collision?

m/s

6) Compare the initial and final kinetic energy of the total system before and after the collision:

KE_i = KE_f

KE_i > KE_f

KE_i < KE_f

Solution

momentum = mass * velocity

= 435 kg * 21 m/s = 9135 kg.m/s

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momentum = mass * velocity

= 1298 * 10 = 12980 kg.m/s

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angle after collision = tan^-1(12980 / 9135)

= 54.86°

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total momentum = sqrt [ 9135² + 12980² ]

= 15872

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final velocity = total momentum / total mass

= 15872 / (1298 + 435)

= 9.16 m/s