An array is sorted in ascending order if each element of the

An array is sorted (in ascending order) if each element of the array is less than or equal to the next element .

An array of size 0 or 1 is sorted

Compare the first two elements of the array ; if they are out of order, the array is not sorted; otherwise, check the if the rest of the array is sorted.

Write a boolean -valued  method  named  isSorted that accepts an integer  array , and the number of elements in the array and returns whether the array is sorted.

Solution

SortCheck.java


public class SortCheck {

  
   public static void main(String[] args) {
       System.out.println(isSorted(new int[]{1,2,3,4,5}, 5));
       System.out.println(isSorted(new int[]{1,2,4,3,5}, 5));
   }
   public static boolean isSorted(int a[], int size){
       if(size ==0 || size == 1){
           return true;
       }
       for(int i=0; i<size-1; i++){
           if(a[i] > a[i+1])
               return false;
       }
       return true;
   }

}

Output:

true
false

An array is sorted (in ascending order) if each element of the array is less than or equal to the next element . An array of size 0 or 1 is sorted Compare the f

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