n in terms of n1SolutionAnswer to the question n n n1 n2

n! in terms of (n-1)!

Solution

Answer to the question)

n! = n* (n-1) * (n-2) * ....*3*2*1

(n-1)! = (n-1) * (n-2) * (n-3) * ....* 3*2*1

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Thus n! = n * (n-1)!