When a capacitor has a charge of magnitude 600 mu C on each

When a capacitor has a charge of magnitude 60.0 mu C on each plate, the potential difference across the plates is 12.0 V. How much energy is stored in this capacitor when the potential difference across its plates is 120. V?

Solution

Answer:

Capacitance of capacitor = Q/V = 60 x 10^-6 / 12 = 5 x 10^-6 Farad

Energy stored = (1/2)CV² = 0.5 x 5 x 10^-6 x 120 x 120 = 3.6 x 10^-2 Joule