Find the dimension of each a The space of cubic polynomials
Find the dimension of each.
(a) The space of cubic polynomials p(x) such that p(7) = 0
(b) The space of cubic polynomials p(x) such that p(7) = 0 and p(5) = 0
Solution
a) Given that space of cubic polynomials p(x) such that p(7) = 0
Let p(x) = ax3+bx2+cx+d --------eq (1)
Given that p(7) = 0
a(7)3+ b(7)2+c.7 +d=0
243 a + 49b + 7c +d = 0
d = -243 a -49b - 7c
Substitute value of d in eq (1),
p(x) = ax3+bx2+cx -243 a -49b - 7c
p(x) = a (x3-243) +b (x2-49) +c (x-7)
Therefore,
dimension = { x-7 ,x2-49, x3-243 } = 3
(OR)
Given that p(7) = 0
Then,
p(x) = (x-7) (a+bx+cx2)
p1(x) = (x-5) , p2(x) = x (x-7) , p3(x) = x2 (x-7) forms the basis.
Therefore,
dimension the space = 3
b) Given that
p(7) = 0 and p(5) = 0
Then,
p(x) = (x-5) (x-7) (a+bx)
p1(x) = (x-5) (x-7) , p2(x) = x (x-5) (x-7) forms the basis.
Therefore,
dimension the space = 2

