Response to Living with Humans numbers of alleles for the or

Response to Living with Humans? numbers of alleles for the original naive population. Once you know the numbers for each allele, calculate the frequency of each allele (p and q) to tw a of individuals Genotype (phenotype) in original of glut alleles. a of glu alleles Total a of alleles population glu /glut (glucose attracted) 180 glut /glu (intermediate) glu /glu (glucose averse) 100 Allele frequency p My Answers Give Up

Solution

in the total population with 2 alleles, from the phenotype it can be calculated as below:

(p)glu+/glu+ has 180 glu+ alleles, 0 glu- alleles as it contains homozygous alleles

glu+/glu- has 7 glu+ alleles, 7 glu- alleles, as it has heterozygous alleles

(q) glu-/glu- has 6 glu-alleles has homozygous alleles

p+q=1, p2+2pq+q2=1

here p²=0.9 from the given phenotype (90/100), so p=0.94 and q=1-0.94=0.06

or

alleles have been given so glu+ alleles are 180+ 7(7 glu+ and 7glu-)=187/200=0.935

glu-alleles are 6+7=13/200=0.065.

so p allele frequency is 0.935 and q allele is 0.065