can soneone help me with question 123SolutionSimplifying 2x2



can soneone help me with question 123?

Solution

Simplifying

(2x2 + y) * dx + (x2y + -1x) * dy = 0

Reorder the terms for easier multiplication:

dx(2x2 + y) + (x2y + -1x) * dy = 0

(2x2 * dx + y * dx) + (x2y + -1x) * dy = 0

Reorder the terms:

(dxy + 2dx3) + (x2y + -1x) * dy = 0

(dxy + 2dx3) + (x2y + -1x) * dy = 0

Reorder the terms:

dxy + 2dx3 + (-1x + x2y) * dy = 0

Reorder the terms for easier multiplication:

dxy + 2dx3 + dy(-1x + x2y) = 0

dxy + 2dx3 + (-1x * dy + x2y * dy) = 0

dxy + 2dx3 + (-1dxy + dx2y2) = 0

Reorder the terms:

dxy + -1dxy + dx2y2 + 2dx3 = 0

Combine like terms: dxy + -1dxy = 0

0 + dx2y2 + 2dx3 = 0

dx2y2 + 2dx3 = 0

Solving

dx2y2 + 2dx3 = 0

Solving for variable \'d\'.

Move all terms containing d to the left, all other terms to the right.

Factor out the Greatest Common Factor (GCF), \'dx2\'.

dx2(y2 + 2x) = 0

Subproblem 1

Set the factor \'dx2\' equal to zero and attempt to solve:

Simplifying

dx2 = 0

Solving

dx2 = 0

Move all terms containing d to the left, all other terms to the right.

Simplifying

dx2 = 0

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor \'(y2 + 2x)\' equal to zero and attempt to solve:

Simplifying

y2 + 2x = 0

Reorder the terms:

2x + y2 = 0

Solving

2x + y2 = 0

Move all terms containing d to the left, all other terms to the right.

Add \'-2x\' to each side of the equation.

2x + -2x + y2 = 0 + -2x

Combine like terms: 2x + -2x = 0

0 + y2 = 0 + -2x

y2 = 0 + -2x

Remove the zero:

y2 = -2x

Add \'-1y2\' to each side of the equation.

y2 + -1y2 = -2x + -1y2

Combine like terms: y2 + -1y2 = 0

0 = -2x + -1y2

Simplifying

0 = -2x + -1y2

 can soneone help me with question 123?SolutionSimplifying (2x2 + y) * dx + (x2y + -1x) * dy = 0 Reorder the terms for easier multiplication: dx(2x2 + y) + (x2y
 can soneone help me with question 123?SolutionSimplifying (2x2 + y) * dx + (x2y + -1x) * dy = 0 Reorder the terms for easier multiplication: dx(2x2 + y) + (x2y
 can soneone help me with question 123?SolutionSimplifying (2x2 + y) * dx + (x2y + -1x) * dy = 0 Reorder the terms for easier multiplication: dx(2x2 + y) + (x2y

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