Imagine that the average satisfaction level among Remingtons

Imagine that the average satisfaction level among Remington’s patrons is 4 (on a scale of 1– 7), with standard deviation of .5.

Refer to the empirical rule on p. 270 of from Understanding Basic Statistics and calculate the range of satisfaction levels for:

Approximately 68% of the patrons

Approximately 95% of the patrons

Approximately 99.7% of the patrons

Solution

Approximately 68% of the patrons are in the range (4-0.5,4+0.5) = (3.5,4.5).

Approximately 95% of the patrons are in the range (4-2*0.5,4+2*0.5) = (3,5).

Approximately 99.7% of the patrons are in the range (4-3*0.5,4+3*0.5) = (2.5,5.5).