A new printer can print a set of newsletters in 15 minutes l
Solution
Let x be the numberof minutes that the old printer takes to print the newsletter alone. Then, the time taken by the new printer to print the newsletter alone is x - 15 minutes. When the two printers work together, the job is done in 40 minutes. The old printer finishes 1/x of the job in 1 minute and the new printer finishes 1/ (x -15) of the job in 1 minute. Therefore, the 2 printers , working simultaneously, finish ( 1/x) + (1/x -15) of the job in 1 minute. Therefore, ( 1/x) + (1/x -15) = 1/40 or, (2x -15)/ x ( x -15) = 1/40 or, 40(2x -15) = x ( x -15) or, 80 x - 600 = x2 -15x or, x2 - 95x + 600 = 0 . Therefore, x = [ 95 ± { (95)2 - 4*1*600} ]/2*1 = [95 ± (9025 - 2400)]/2 = (95 ± 6625)/2 = ( 95 ± 81.39)/2 . Thus, either x = 6.805 minutes or, x = 88.20 mintes. Now, x cannot be 6.805 minutes, because then the new printer will take negative time to print the newsletter which is not possible. Therefore x = 88.20 minutes. Thus, the old printer takes approximately 88.20 minutes to print the set of newsletters.
